import re# line = 'ahhuuhhaaahhhhang123'#line = 'ahuuuhuuu'# 需要获取h和h之间,需要包含特定数量字符的子串# 使用 + h和h之间至少要有一个字符# {} 限定它前面出现的那个东西的出现次数# match_res = re.search('h.{3,6}h', line)# if match_res:# print(match_res)# print(match_res.group(0))# # print(match_res.group(1))# # print(match_res.group(2))# print('ojbk')# else:# print('no ojbk')## match_res = re.search('h.+?h', line)# if match_res:# print(match_res)# print(match_res.group(0))# # print(match_res.group(1))# # print(match_res.group(2))# print('ojbk')# else:# print('no ojbk')## line = 'sss127aaaanbsss127'## # 匹配sss127 或者 aaa# # 或者# match_res = re.search('(sss127|aaa)', line)# if match_res:# print(match_res)# print(match_res.group(0))# # print(match_res.group(1))# # print(match_res.group(2))# print('ojbk')# else:# print('no ojbk')# [] 匹配中括号内部的任意一个字符line = 'sss127aaaanbsss127'match_res = re.search('([27s1]+)', line)if match_res: print(match_res) print(match_res.group(0)) # print(match_res.group(1)) # print(match_res.group(2)) print('ojbk')else: print('no ojbk')